Class 10 Maths Formulas

CHAPTER 7
COORDINATE GEOMETRY
1.The distance of a point from the
y-axis is called the
x-coordinate (Abscissa).
2.The distance of a point from the
x-axis is called the
y-coordinate (Ordinate).
3.Any point on the
x-axis
is of the form
( x , 0 ).
4.Any point on the
y-axis
is of the form
( 0 , y ).
5.If point
A
is
( x₁ , y₁ )
and point
B
is
( x₂ , y₂ ).
Distance $$\mathrm{AB}=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$$
6. Distance of a point $$\mathrm{A}(\mathrm{x}, \mathrm{y})$$ from the origin $$\mathrm{O}=\mathrm{OA}=\sqrt{(x)^{2}+(y)^{2}}$$
7. Distance of a point $$\boldsymbol{P}(\boldsymbol{x}, \boldsymbol{y})$$ from the $$\boldsymbol{x}$$-axix is $$|\boldsymbol{y}|$$ units.
8. Distance of a point $$\boldsymbol{P}(\boldsymbol{x}, \boldsymbol{y})$$ from the $$\boldsymbol{y}$$-axix is $$|\boldsymbol{x}|$$ units
9.Three points $$\mathrm{A}, \mathrm{B}, \mathrm{C}$$ are collinear if the sum of the distances between two pairs of points = the distance between the third pair.

Coordinate geometry

$$P Q+Q R=P R . P, Q, R$$ are collinear points.
$$A C+C B \neq A B$$. A, B. C are non collinear points.
10. SECTION FORMULA :
INTERNAL DIVISION :
$$P(x, y)$$ divides the line joining $$A\left(x_{1}, y_{1}\right)$$ and $$B\left(x_{2}, y_{2}\right)$$
in the ratio $$m: n$$ internally.
$$\mathrm{P}(\mathrm{x}, \mathrm{y})=\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+m y_{1}}{m+n}$$

Coordinate geometry

EXTERNAL DIVISION :
$$P(x, y)$$ divides the line joining $$A\left(x_{1}, y_{1}\right)$$ and $$B\left(x_{2}, y_{2}\right)$$ in the ratio $$m: n$$ externally.
$$\mathrm{P}(\mathrm{x}, \mathrm{y})=\frac{m x_{2}-n x_{1}}{m-n}, \frac{m y_{2}-m y_{1}}{m-n}$$

Coordinate geometry

11. MID – POINT FORMULA :
If $$P(x, y)$$ is the midpoint of the line joining $$A\left(x_{1}, y_{1}\right)$$ and $$B\left(x_{2}, y_{2}\right)$$
$$\boldsymbol{P}(\boldsymbol{x}, \boldsymbol{y})=\frac{x_{2}+x_{1}}{2}, \frac{y_{2}+y_{1}}{2}$$
12.Points of Trisection:
The points which divide the line joining
A and B in the ratio
2 : 1 and 1 : 2
are called the points of trisection.
13.To prove that a quadrilateral is a
Parallelogram,
(given the vertices), prove that the midpoints of both the diagonals
are the same.
Use the same concept to find the
fourth vertex
of the parallelogram if three vertices in order are given.
14.To prove that the quadrilateral is a
Rectangle,
(given the vertices), prove that the
opposite sides are equal
and the
two diagonals are equal.
15.To prove that the quadrilateral is a
Rhombus,
(given the vertices), prove that
all four sides are equal.
Diagonals are not equal. The diagonals of a rhombus bisect each other
at right angles. (Important property of a Rhombus)
16.To prove that the quadrilateral is a
Square,
(given the vertices), prove that
all four sides are equal
and the
two diagonals are equal.