Polynomials
Previous Year Solved Questions 2019
Q1: Find the value of k such that the polynomial x² – (k+6)x + 2(2k-1) has the sum of its zeroes equal to half of its product. [Year 2019, 3 Marks]
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Ans: k = 7
Given polynomial: x² – (k+6)x + 2(2k-1)
Given polynomial: x² – (k+6)x + 2(2k-1)
Sum of zeroes = (k+6)
Product of zeroes = 2(2k-1)
Given: Sum = ½ × Product
k+6 = ½ × 2(2k-1)
k+6 = 2k-1
6+1 = 2k – k
7 = k